What is the molarity of a KF (aq) solution containing 116 grams of KF in 1.00 liter of solution?
A. 1.00 M
B. 2.00 M
C. 3.00 M
D. 4.00 M
Step 1: find the moles of solute using the formula:
mass of solute (g) divided by formula mass of solute
Step 2: divide the moles of solute by volume of solution in liters M / V.
Or if you know the moles of solute,
Molarity = moles of solute divided by volume of solution in liters . KF has a formula mass of 39 + 19 or 58 g/mole. Since 116 grams are given, 116g / 58g/mole = 2 moles of solute.
To find the Molarity, take 2 moles of solute and divide by 1 L of solution.
2 moles / 1 L = 2.00 M solution
1 of 48
1465 Points
Been a pharmacist for about three years now.
Exam Details
This set of PCAT Chemistry questions has been donated by The PCAT Professor.
Taken: 8,252 times
Added: 8/11/2008
Liked: 6 times
Audience: University / College

Study Groups Using this Exam
1,160 Members
This is a study guide to help future pharmacists prepare for the PCAT.

Be the first to comment on this exam.