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What is the molarity of a KF (aq) solution containing 116 grams of KF in 1.00 liter of solution?
A. 1.00 M
B. 2.00 M
C. 3.00 M
D. 4.00 M
Molarity
Step 1: find the moles of solute using the formula:
mass of solute (g) divided by formula mass of solute
Step 2: divide the moles of solute by volume of solution in liters M / V.
Or if you know the moles of solute,
Molarity = moles of solute divided by volume of solution in liters . KF has a formula mass of 39 + 19 or 58 g/mole. Since 116 grams are given, 116g / 58g/mole = 2 moles of solute.
To find the Molarity, take 2 moles of solute and divide by 1 L of solution.
2 moles / 1 L = 2.00 M solution
 
 
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JPlantesMD
18047 Points
I wrote the MCAT about 8 years ago. During that time I created a whole lot of study material for myself and my friends. I want to now share it with the world. Good luck :)
 
 
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Taken: 164 times
Added: 7/2/2008
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JPlantesMD
Founded by JPlantesMD
While these questions do not fit the MCAT format (they have no related reading passages) they cover concepts one should understand in order to do well in the physical sciences portion of the MCAT.
 
 
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